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1/64=16^2a
We move all terms to the left:
1/64-(16^2a)=0
We multiply all the terms by the denominator
-16^2a*64+1=0
Wy multiply elements
-1024a^2+1=0
a = -1024; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-1024)·1
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4096}=64$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-64}{2*-1024}=\frac{-64}{-2048} =1/32 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+64}{2*-1024}=\frac{64}{-2048} =-1/32 $
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